Joshua's math-ology

Get it fast, get it right

Minorities stick together

Consider the following scenario.

How many ways can you arrange the shoes, so that the black shoes must always be together?

Before we tackle this problem, let’s simplify it a little. Let’s imagine they are all in a straight line. B = black shoes, T = tri-coloured shoes. Let’s try to see all the possibilities.

B B T T T T =   5  x  4  x  3  x  2  x  1  x  2  =  240

Therefore, the total number of possibilities are 240.

Now, back to the scenario.

If we arrange the shoes in a circle, will the answer be the same?

Advertisements

August 27, 2010 - Posted by | Additional Mathematics Form 5

No comments yet.

Leave a Reply

Fill in your details below or click an icon to log in:

WordPress.com Logo

You are commenting using your WordPress.com account. Log Out / Change )

Twitter picture

You are commenting using your Twitter account. Log Out / Change )

Facebook photo

You are commenting using your Facebook account. Log Out / Change )

Google+ photo

You are commenting using your Google+ account. Log Out / Change )

Connecting to %s

%d bloggers like this: